Torsion Shaft Diameter

Determine minimum shaft diameter under torsion for solid or hollow shafts from allowable shear stress.

Inputs

Formula

Solid d = ∛(16T/(π[τ])); Hollow dₒ = ∛(16T/(π(1−k⁴)[τ]))
Tτ = T·r / J (J = π d⁴ / 32)
Torsion Shaft Diameter schematic

Fundamentals

A shaft under torsion carries shear stress — central to strength and stiffness of drive shafts.

Max surface shear $\tau=Tr/J=T/W_t$, polar moment $J=\pi d^4/32$, torsional section modulus $W_t=\pi d^3/16$. Twist per length $\varphi=T/(GJ_p)$.

History

Torsional shear stress and polar moment theory for circular shafts was laid by Coulomb (1784) and Saint-Venant (1855).

Engineering applications

Used for drive shafts, drill strings and torque wrenches that carry pure torsion in circular sections.

Glossary

Torque $T$Couple that rotates the shaft about its axis.
Shear $\tau$In-plane internal stress, max at the surface.
Polar moment $J$Geometric resistance to twist.

How to use

  1. Fill in Torque T, Allow. shear [τ], Hollow ratio k (0=solid) in the Inputs section (watch the unit on each field).
  2. Click Calculate; the tool evaluates the formula shown above.
  3. Read Solid dia., Hollow outer (k>0) in the results area.
Formula notesTorsional shear τ = T·r / J; solid J = π d⁴/32, d = ∛(16T/(π·τ)); hollow J = π d⁴(1−k⁴)/32.

Formula · Worked Example · Knowledge

Formula

Solid shaft under torsion: $d=\sqrt[3]{16T/(\pi[\tau])}$; hollow $d_o=\sqrt[3]{16T/(\pi(1-k^4)[\tau])}$ (T in N·mm).

Worked Example

T=400 N·m, [τ]=45 MPa → d≈27.2 mm (solid).

Key Points

  • Hollow shafts are lighter at equal strength — good for high speed.
  • Use lower allowable stress for reversing torque.
  • With bending, use combined method (see related tools).

Parameters

Inputs

ParameterSymbolUnitDefault
Torque T (N·m)TN·m400
Allow. shear [τ] (MPa)tauMPa45
Hollow ratio k (0=solid)k0

Outputs

ResultSymbolUnit
Solid dia.d_solidmm
Hollow outer (k>0)d_hollowmm

Applications

  • Common engineering use cases

FAQ

What formula does this tool use?
This tool computes per ISO / AGMA / ASME standard formulas: Solid d = ∛(16T/(π[τ])); Hollow dₒ = ∛(16T/(π(1−k⁴)[τ]))
How accurate are the results?
Results match input precision, based on SI units and common engineering approximations; for critical duty re-check with a safety factor.
Where is it used?
Common engineering use cases