Thread Engagement Length

Verify thread-flank shear and bearing stress at engagement length L and compute required minimum length (ISO 261 / GB metric threads).

Inputs

Formula

τ = F/(0.5πdL); σc = F/(0.75πdL); L_req = F/(0.5πd·[τ])
Lₑ engagementEngagement length ensures joint strength
Thread Engagement Length schematic

Fundamentals

Engagement length is the effective axial length where internal and external threads mesh, governing joint strength and locking.

Engagement $L_e$ must give enough thread-flank area to transfer load; too short shears, too long adds little strength but costs machining. Typically $L_e\ge0.8d$ adjusted by duty.

History

The effect of engaged threads on joint strength came from early thread-failure statistics; ISO 965 defines deviations and engagement-length series.

Engineering applications

Used for threaded pairs under alternating or impact load, e.g. lifting-eye bolts and hoist studs, to prevent stripping.

Glossary

Engagement $L_e$Axial length of effective thread mesh.
Pitch $P$Axial distance between adjacent thread crests.
Nominal dia $d$Major diameter defining the thread size.

How to use

  1. Fill in Axial force F, Major dia. d, Engagement L, Allow. shear [τ], Allow. bearing [σc] in the Inputs section (watch the unit on each field).
  2. Click Calculate; the tool evaluates the formula shown above.
  3. Read Actual shear τ, Bearing stress σc, Required length L_req in the results area.
Formula notesThread engagement Le sets joint strength; typically Le ≥ 0.8 d (steel–cast iron) or ≥ 1.0 d (steel–aluminium).

Formula · Worked Example · Knowledge

Formula

Thread shear $\tau=F/(0.5\pi d L)$, bearing stress $\sigma_c=F/(0.75\pi d L)$; min engagement $L_{req}=F/(0.5\pi d[\tau])$.

Worked Example

F=10000 N, d=10 mm, [τ]=120 MPa → L_req≈5.3 mm (15 mm used for margin).

Key Points

  • Short engagement shears the flank or crushes the nut.
  • Coarse ISO 261 threads often use L≥0.8d.
  • Check the weaker of internal/external thread materials.

Parameters

Inputs

ParameterSymbolUnitDefault
Axial force F (N)FN10000
Major dia. d (mm)dmm10
Engagement L (mm)Lmm15
Allow. shear [τ] (MPa)tau_allowMPa120
Allow. bearing [σc] (MPa)sigc_allowMPa200

Outputs

ResultSymbolUnit
Actual shear τtauMPa
Bearing stress σcsigcMPa
Required length L_reqL_reqmm

Applications

  • Common engineering use cases

FAQ

What formula does this tool use?
This tool computes per ISO / AGMA / ASME standard formulas: τ = F/(0.5πdL); σc = F/(0.75πdL); L_req = F/(0.5πd·[τ])
How accurate are the results?
Results match input precision, based on SI units and common engineering approximations; for critical duty re-check with a safety factor.
Where is it used?
Common engineering use cases